(1)sin(-x-5π)· cos(x-π/2)-tan(2π-x)=( )(2)0≤x≤2π且sinx>根号3 cosx,则x的取值范围为( ) (3)已知向量a=(sinθ,-2),b=(1,cosθ)且a⊥b(0
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/28 04:25:12
(1)sin(-x-5π)· cos(x-π/2)-tan(2π-x)=( )(2)0≤x≤2π且sinx>根号3 cosx,则x的取值范围为( ) (3)已知向量a=(sinθ,-2),b=(1,cosθ)且a⊥b(0
(1)sin(-x-5π)· cos(x-π/2)-tan(2π-x)=( )
(2)0≤x≤2π且sinx>根号3 cosx,则x的取值范围为( )
(3)已知向量a=(sinθ,-2),b=(1,cosθ)且a⊥b(0
(1)sin(-x-5π)· cos(x-π/2)-tan(2π-x)=( )(2)0≤x≤2π且sinx>根号3 cosx,则x的取值范围为( ) (3)已知向量a=(sinθ,-2),b=(1,cosθ)且a⊥b(0
(1)[sin x]^2+tan x
(2)π/3
化简1+sin x/cos x·sin2x/2cos²(π/4-x/2)
sin(sin(sin(sin(x)=cos(cos(cos(cos(x),X等于多少?
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
若f(sin x+cos x)=sin x·cos x,则f(cos 派/6)=?
sin(5x)-sin(3x)= 根号2cos(4x)1.sin(5x)-sin(3x)= (根号2)cos(4x)解方程2.sin(x)+sin(2x)+sin(3x)=1+cos(x)+cos(2x)
已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于?已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于() A.-2009 B.-1/2009 C.1/2009 D.2009
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x
一道数学题:sin(π+x)=1/5,则cos(π-x)=?
化简sin(2π+x)cos(π-x)sin(π-x)/cos(x-π)sin(-π-x)sin(π+x)
sin(-x) cos(-x)等于多少
sin x(sin x+cos x)=1求x等于多少
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
cos x/sin x+sin x/(1+cos x) 化简.
f(x)=sin x +cos x +sin x * cos x ,求值域
求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2).
已知tanx=根号下2 求:1)(sin x+cos x)/(cos x -sin x)的值.2)2sin^2 x-sin x cos x+cos^2 x 的值
tanx=m,则{sin(x+3π)+cos(π+x)}/{sin(-x)-cos(π+x)}=?
[(sin x-cos x)/(sin x+cos x)]^4 求定积分 积分区间0-π/4