若x∧2-y∧2=24,x+y=6,x+2y=?

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若x∧2-y∧2=24,x+y=6,x+2y=?
若x∧2-y∧2=24,x+y=6,x+2y=?

若x∧2-y∧2=24,x+y=6,x+2y=?
x-y
=(x-y)(x+y)/(x+y)
=(x²-y²)/(x+y)
=24/6
=4
与x+y=6 联立
2x=10
x=5
y=6-x=6-5=1
x+2y=5+2x1=7
如果本题有什么不明白可以追问,

x²-y²=(x+y)(x-y)=24
x+y=6
所以x-y=4
相加
2x=10
x=5
y=6-x=1
所以x+2y=7

x∧2-y∧2=24
(x+y)(x-y)=24
x+y=6
x-y=4
x=5,y=1

x+2y=5+2=7

满意请采纳,O(∩_∩)O谢谢~

x+y=6
∴x-y=(x+y)(x-y)/(x+y)
=(x²-y²)/(x+y)
=24/6
=4
解得x=5, y=1
x+2y=5+2=7


x²-y²=24, x+y=6
x²-y²=(x-y)(x+y)=24
∴x-y=4
x+y=6
解得: x=5
y=1
∴x+2y=5+1×2=7.

x²-y²=(x+y)(x-y)=6(x-y)=24
∴x-y=4
与x+y=6联立方程组,解得:
x=5,y=1
∴x+2y=5+2=7

7


x²-y²=24, x+y=6
x²-y²=(x-y)(x+y)=24
∴x-y=4
x+y=6
解得:x=5,y=1
∴x+2y=5+1×2=7.
望采纳。