设int x=9,y=9,则printf("%d,%d\n",x--,--y);语句的输出结果是

设int x=9,y=9,则printf(%d,%d ,x--,--y);语句的输出结果是 设int x=12,y=12345;则执行语句printf(x=%4d,y=%4d,x,y);的结果是? #define PR(x,y,z) printf(%d %d %d ,x,y,z) main() { int x,y,z; x=(9+6)%5>=9%5+6%5; printf#define PR(x,y,z) printf(%d %d %d ,x,y,z)main(){int x,y,z;x=(9+6)%5>=9%5+6%5;printf(%d ,x);z=x?(y=x):(y=++x);PR(x,y,z);} #include int main() { int max; int x,y,z; if x>y printf(max=x); else printf(max);if max #include main() { int x=3,y; do { y=x--; if(!y) {printf(*);continue;} printf(#); }whi下面程序段____________#include main(){int x=3,y;do{y=x--;if(!y){printf(*);continue;}printf(#);}while(1 int x,y; x=13; y=5; {printf(%d,x%=(y/=2)); int x=3,y=4; printf(%d,%d,(x.y),(y,x)); int x=20;printf(“%d”,0 int x=20;printf(“%d”,0 int x=17,y=26; printf (%d,y/=(x%=6));解释一下 main() { int x=2002,y=2003; printf(%d ,(x,y)); } 为什么结果是2003? main() { int x=2002,y=2003; printf(%d ,(x,y)); } void fun(int *x,int y){printf(%d%d,*x,*y);*x=3;*y=4;}main(){int x=1,y=2;fun(&y,&x);printf(%d%d,x,y);} void fun(int x,int y) {x=x+y;y=x-y;x=x-y; printf(%d,%d,,x,y); } main() {int x=2,y=3; fun(x,y); privoid fun(int x,int y){x=x+y;y=x-y;x=x-y;printf(%d,%d,,x,y);}main(){int x=2,y=3;fun(x,y);printf(%d,%d ,x,y);} #include main() { int x=1,y=3; x=9-(--y)-(--y); printf(%d,x); } #include main()#includemain(){ int x=1,y=3; x=y*4.8/2; printf(%d,x);}谁能帮我解释下这两个程序的运行过程? # include void p(int *x,int y){ ++*x; y=y+2; } void main() { int x=2,y=3; p(&y,y); printf(# includevoid p(int *x,int y){++*x;y=y+2;}void main(){int x=2,y=3;p(&y,y);printf(%d#%d,x,y);} 谁来帮我找找错啊int max(int a,int b);void main(){int x,y,z;int max(int a,int b);printf(input two numbers: );scanf(%d%d,&x,&y);z=max(x,y);printf(maxmum=%d,z);}int max(int a,int b);{if(a>b) return a;else return b;}------------------Con #include main(){int a[]={1,2,3,4,5,6,7,8,9,0},*p; p=a; printf(%x ,p);printf(%x ,p+9提问是这样的,若一个int类型的变量占两字节,第一个printf语句输出194,则第二个printf语句输出的结果是多少?