1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

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1/(m^2-m)+(m-5)/(2m^2-2) 分式计算
1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

1/(m^2-m)+(m-5)/(2m^2-2) 分式计算
1/(m^2-m)+(m-5)/(2m^2-2)
=1/[m(m-1)]+(m-5)/[2(m+1)(m-1)]
=2(m+1)/[2m(m+1)(m-1)]+m(m-5)/[2m(m+1)(m-1)]
=[2(m+1)+m(m-5)]/[2m(m+1)(m-1)]
=(m²-3m+2)/[2m(m+1)(m-1)]
=(m-1)(m-2)/[2m(m+1)(m-1)]
=(m-2)/[2m(m+1)]

=1/m(m-1)+(m-5)/2(m+1)(m-1)
=[2(m+1)+m(m+5)]/[2m(m+1)(m-1)]
=(2m+2+m^2+5m)/[2m(m+1)(m-1)]
=(m^2+7m+2)/(2m^3-2m)

m*m-5m-1=0则2m*m-5m+1/m*m 化简|6-m|-|2m+1|+|m+5| (m 计算：（m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m) (m+3m+5m+...+2009m)-(2m+4m+6m+...2008m) (m+3m+5m+...+2014m)-(2m+4m+6m+...+2013m) (m+3m+5m+...+2013m)-(2m+4m+6m+...+2012m) (m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)= 计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m) m-2m-3m+4m-5m-6m+7m.2004m=? (m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=? 已知m*m+m-1=0,求m*m*m+2m*m-2005 4m(m的平方-2m-1)+m(2m+5)(5-2m) m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m求m的值 2m^2-5m+1/m^2 怎么等于(m^2-5M)+m^2+1/m^2 计算M-M^2/M^2-1*M-1/M除以(M-1/M+1)^2 (m+3m+5m+...+2009m)-(2m+4m+...+2008m)怎么算 合并同类项m-2m+3m-4m+5m-.+2011m-2012m m+3m+5m+...+2011m-2m-4m-...-2010m等于多少?