若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少
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若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少
若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少
若x/3=y/4=z/5(xyz≠0),则x+y+z/2x=多少
设x/3=y/4=z/5=k
则x=3k,y=4k,z=5k
(x+y+z)/2x
=(3k+4k+5k)/6k
=12k/6k
=2
x/3=y/4=z/5
所以
y=(4/3)*x
z=(5/3)*x
所以
(x+y+z)/(2x)
=[x+(4/3)*x+(5/3)*x]/(2x)
=(1+4/3+5/3)/2
=2
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