0,9,26,65,124() A.165 B.193 C.217 D.239从中选数列

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 03:11:49

0,9,26,65,124() A.165 B.193 C.217 D.239从中选数列
0,9,26,65,124() A.165 B.193 C.217 D.239从中选数列

0,9,26,65,124() A.165 B.193 C.217 D.239从中选数列
1的三次方-1=0
2的三次方+1=9
3的三次方-1=26
4的三次方+1=64
5的三次方-1=124
6的三次方+1=217
C

已知a满足等式a^2-a-1=0,求代数式a^8+7a^-4的值解:由a^2-a-1=0得,a^2=a+1, 于是a^4=(a+1)^2=a^2+2a+1=3a+2 a^8=(3a+2)^2=9a^2+12a+4=21a+13 a^8+7a^-4=21a+13+7/(3a+2) =(63a^2+81a+26+7)/(3a+2) =(63a+63+81a+33)/(3a+2) =(144a+96)/(3a+2)=48 请 公务员数量关系题(请详细说明)一、65,35,17,3,( )A.1 B.2 C.0 D.4二、215,124,63,( )A.8 B.9 C.26 D.15三、2,3,8,( )A.62 B.63 C.64 D.65四、2/3,8/9,3/4,2,( )A.3 B.23/9 C.25/9 D.26/9五、3/7,1/2,7/13,9/16,( )A.13/18 B.12/19 C.11/19 D 0,9,26,65,124() A.165 B.193 C.217 D.239从中选数列 求数列:0,9,26,65,124,( )A.186 B.217 C.216 D.215 0,9,26,65,124,( ) A.165 B.193 C.217 D.239 已知a>0,b>0,1/a+9/b=1,求证:a+b≥16 已知a>0,b>0,求证:1/a+9/b>16/(a+b) 这三题怎么解(数学推理题)43 .0 ,9,26,65,124,( ) A .165 B .193 C .217 D .239 44 .0 ,4,16,40,80,( ) A .160 B .128 C .136 D .140 45 .0 ,2,10,30,( ) A .68 B .74 C .60 D .70 解一元二次方程组16a*a-4(3-4a)<0(a-1)*(a-1)-4a*a<04a*a+8a<0 公务员数列题目42 .1 ,3,4,1,9,( ) A .5 B .11 C .14 D .64 43 .0 ,9,26,65,124,( ) A .165 B .193 C .217 D .239 44 .0 ,4,16,40,80,( ) A .160 B .128 C .136 D .140 45 .0 ,2,10,30,( ) A .68 B .74 C .60 D 求和:1,a+a^2,a^3+a^4+a^5,a^6+a^7+a^8+a^9,···(a不等于0) 分式的乘除:16-a平方/a平方+8a+16÷a-4/2a+8乘a-2/a+281-a平方/a平方+6a+9÷a-9/2a+6乘a+3/a+9 数列问题答案和理由请告知下2 ,12,36,80,( ) A .100 B .125 C .150 D .175 1 ,3,4,1,9,( ) A .5 B .11 C .14 D .64 0 ,9,26,65,124,( ) A .165 B .193 C .217 D .239 0 ,4,16,40,80,( ) A .160 B .128 C .1 ..(思路麻烦解释下)(1) 0,6 ,24,60,120,210,)A.280,B 32,C 334 ,D 336(2)0 ,9,26,65,124(?)A 186,B 217,C 216,D215(3)1 ,4 ,27,256,)A 625,B1225,C 2225,D3125(4)65,35,17,3,9(?)A 1,B 2,C 0 ,D 4 0,9,26,65,124,(A.186 B.215 C.216 D.21734,36,35,35,(),34,37(A.36,33 B.33,36 C.37,34 D.34,37√2,3,√28,√65,(A.2√14 B.√83 C.4√14 D.3√142,3,6,36,(A.48 B.54 C.72 D.1296 初三数学题一元二次方程已知a^2-4a-b/2+65/16=0,求a^2-4倍的根号B的值a^2就是A的平方,那a^3就是A的三次方了 已知a^2+2a-1=0,求(a^2-16)/(a^3+4a^2+4a)乘以(a+2)/(a-4)除以(a+4)+3 已知a^2-3a+1=0,求a+1/a,a^2+1/a^2,a^2-1/a^2,a^3+1/a^3,4a^2-9a-2+9/(1+a^2)