数列{An}是等差数列,a4=7,则s7=

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数列{An}是等差数列,a4=7,则s7=
数列{An}是等差数列,a4=7,则s7=

数列{An}是等差数列,a4=7,则s7=
可设通项An=A1+(n-1)d.
易知
Sn=[2A1+(n-1)d]n/2
由题设,A4=A1+3d=7
S7=[2A1+6d]×7/2
=7[A1+3d]
=7×7
=49
∴S7=49

s7=a1+a2+...+a7=7a4=7*7=49

s7=a1+a2+a3+a4+a5+a6+a7=a4-3d+a4-2d+a4-d+a4+a4+d+a4+2d+a4+3d=7a4=49

S7=a1+a2+a3+...+a7=a1+a7+a2+a6+a3+a5+a4=7a4=49

a1+a7=2a4
a2+a6=2a4
a3+a5=2a4,
所以a1+a2+a3+a4+a5+a6+a7=(a1+a7)+(a2+a6)+(a3+a5)+a4=7a4=7*7=49

Sn = [ a1 + an ] * n/2
s7 = ( a1 + a7) * 7 ÷ 2
= 2 * a4 * 7 ÷ 2
= 2 * 7 * 7 ÷ 2
= 49