0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
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0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
0.12+0.23+0.34+0.45+0.56
注意!都是循环的,例如0.12的12循环,0.23的23循环
0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
0.12+0.23+0.34+0.45+0.56
=12/99+23/99+34/99+45/99+56/99
=170/99
=1.717171……
(答案绝对正确!这是涉及到怎样把循环小数化成分数的知识.)
=(0.1+0.2+0.3+0.4+0.5)+(0.02+0.03+0.04+0.05+0.06)
=1.5+0.2
=1.7
12/99+23/99+34/99+45/99+56/99=170/99
等于0.17的17循环(*^__^*)
表问为什么,计算器嗯出来的
(0.12+0.89)*8/2=1.01*4=4.04 等差数列 原式=(0.1+0.8)0.12+0.89=1.01 0.23+0.78=1.01 0.34+0.67=1.01 0.45+0.
(0.12+0.23+0.34)×(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)×(0.23+0.34)
(0.12+0.23+0.34)*(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)*(032+034)简便计算
0.12+0.23+0.34+0.45+0.56+0.67+0.78+0.89=?
(1+0.23+0.34)*(0.23+0.34+0.45)-(1+0.23+0.34+0.45)*(0.23+0.34)简便运算
(1+0.23+0.34)×(0.23+0.34+0.45)-(1+0.23+0.34+0.45)×(0.23+0.34)
0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)=?
简便运算 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)
(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)=
(1+0.12+0.23)×(0.12+0.23+0.34)- (1+0.12+0.23+0.34)×(0.12+0.23).
(1+0.12+0.23)X(0.12+0.23+0.34)-(1+0.12+0.23+0.34)X(0.12+0.23)=?
(1+0.12+0.23)乘(0.12+0.23+0.34)_(1+0.12+0.23+0.34)乘(0.12+0.23)
0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位
0.12+0.23+0.34+0.45+0.56答案是几 注:都是循环小数,第二位开始
0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位 《2》
简便运算(1+0.12+0.23)X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.23)
(0.12+0.23+0.34)*(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)这是题目,看我打字辛苦的份上帮帮我
(1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)等于几?用简便方法计算!