Gypsum is hydrated calcium sulfat,CaSO4·xH2O.A residue of 5.65g of anhydrous calcium sulfate is obtained by heating 7.15g gypsum.Determine the empirical formula of gypsum不用翻译……尤其是拿翻译软件翻译的……这个太。咳咳要

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Gypsum is hydrated calcium sulfat,CaSO4·xH2O.A residue of 5.65g of anhydrous calcium sulfate is obtained by heating 7.15g gypsum.Determine the empirical formula of gypsum不用翻译……尤其是拿翻译软件翻译的……这个太。咳咳要
Gypsum is hydrated calcium sulfat,CaSO4·xH2O.A residue of 5.65g of anhydrous calcium sulfate is obtained by heating 7.15g gypsum.Determine the empirical formula of gypsum
不用翻译……
尤其是拿翻译软件翻译的……这个太。咳咳
要得是怎么写这个题~

Gypsum is hydrated calcium sulfat,CaSO4·xH2O.A residue of 5.65g of anhydrous calcium sulfate is obtained by heating 7.15g gypsum.Determine the empirical formula of gypsum不用翻译……尤其是拿翻译软件翻译的……这个太。咳咳要
write out the equation first,assume that the number of water is x.
CaSO4.xH2O(136+18x)=CaSO4(136)+xH2O(18x)
无水硫酸钙和x水和硫酸钙的差量为7.15-5.65=1.50g,所以水的质量就是1.5g
列方程
136/5.65=18x/5.0
解得x=2.0
the expirical formula of gypsum is CaSO4.2H2O

翻译:
石膏是水合的钙sulfat，硫酸钙·xH2O. 无水硫酸钙5.65g残
滓通过加热7.15g石膏获得。 确定石膏实验式

加热7.15gGypsum（石膏）可一得到5.65gcalcium sulfate （硫酸钙）
CaSO4·xH2O=CaSO4+xH2O
5.65g divided by 136g/mol equals to 0.042mol
7.15g divided by 0.042mol equals to 172.1 g/mol
172.1g/mol minus 136g...

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加热7.15gGypsum（石膏）可一得到5.65gcalcium sulfate （硫酸钙）
CaSO4·xH2O=CaSO4+xH2O
5.65g divided by 136g/mol equals to 0.042mol
7.15g divided by 0.042mol equals to 172.1 g/mol
172.1g/mol minus 136g/mol equals to 36.1 g/mol
36.1g/mol divided by 18g/mol equals to 2
sothe empirical formula of gypsum is CaSO4·2H2O
看英文其实和看华文没多大区别。

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