若根号下2x-y +|y+2|=0,求代数式[(x-y)²+(x+y)(x-y)]÷2x的值.

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若根号下2x-y +|y+2|=0,求代数式[(x-y)²+(x+y)(x-y)]÷2x的值.
若根号下2x-y +|y+2|=0,求代数式[(x-y)²+(x+y)(x-y)]÷2x的值.

若根号下2x-y +|y+2|=0,求代数式[(x-y)²+(x+y)(x-y)]÷2x的值.
√2x-y +|y+2|=0
∵√2x-y 和|y+2|都≥0
∴y+2=0 y=-2
2x-y=2x+2=0 x=-1
[(x-y)²+(x+y)(x-y)]÷2x
=[(x-y)*2x]/2x
=x-y
=-1+2
=1

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