(-1/2)*(1/2)+1/64*8-(-2/3)*(2/3) 等于多少捏?
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(-1/2)*(1/2)+1/64*8-(-2/3)*(2/3) 等于多少捏?
(-1/2)*(1/2)+1/64*8-(-2/3)*(2/3) 等于多少捏?
(-1/2)*(1/2)+1/64*8-(-2/3)*(2/3) 等于多少捏?
正9分之4
(2+1)(2^2-1)(2^4+1)(2^8+1)(2^16-1)(2^32+1)(2^64+1)
(1-1/2-1/4-1/8-1/16-1/32-1/64)除以1/64注意简算
计算:(1+2)(1+2^2)(1+2^4)(1+2^8)(1+2^16)(1+2^32)(1+2^64)
1/2+1/4+1/8+1/16+1/32+1/64(简算)
1-(1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256)等于( ).
计算3(2²+1)(2⁴+1)(2^8+1)·…·(2^64+1)
加法算式 1/2+1/4+1/8+...+1/32+1/64=( )
数列1,2,4,4,(),8,64
1 1/2 1/8 1/64
(-1/2)*(1/2)+1/64*8-(-2/3)*(2/3) 等于多少捏?
求(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)-2006的末位数字
用平方差公式求出(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^64+1)的值
64 1 / 2 -( 64) 1 / 3= ( ). (A ) 4 ( B ) 12 (C ) 0 ( D ) 8
(1) √27/8 + 1/64 - √1-189/64 - √1-31/256 (2) |-2|-(1+√2)ˇ0+√4谢谢了,
已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1) 求M个位数是几
求值:(2+1)x(2²+1)x(2^4+1)x(2^8+1)...(2^64+10+1
求(2+1)(2^2+1)(2^4+1)(2^8+1)……(2^64+1)-2010的个位数
(m+1)(m^2+1)(m^4+1)(m^8+1)(x^16+1)(x^32)(m^64+1)=