(x-y)/(x²-xy-2y²) - 2/(3x+3y)

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/08 12:33:41

(x-y)/(x²-xy-2y²) - 2/(3x+3y)
(x-y)/(x²-xy-2y²) - 2/(3x+3y)

(x-y)/(x²-xy-2y²) - 2/(3x+3y)
(x-y)/(x^2-xy-2y^2) - 2/(3x+3y)
=(x-y)/[(x+y)(x-2y)]-2/[3(x+y)]
=(3x-3y)/[3(x+y)(x-2y)]-(2x-4y)/[3(x+y)(x-2y)]
=(3x-3y-2x+4y)/[3(x+y)(x-2y)]
=(x+y)/[3(x+y)(x-2y)]
=1/[3x-6y]

（x-y)/(x-2y)(x+y)-2/3(x+y)
=(3x-3y)/3(x-2y)(x+y)-2(x-2y)/3(x-2y)(x+y)
=(x+y)/3(x-2y)(x+y)
=1/3(x-2y)

原式
=（3x²-3y²-2x²+2xy+4y²)/(x²-xy-2y²)(3x+3y)
=（x²+2xy+y²)/(x²-xy-2y²)(3x+3y)
=(x+y)²/(x²+xy-2xy-2y²)3(x+y)
=(x+y)/3[x(...

全部展开

原式
=（3x²-3y²-2x²+2xy+4y²)/(x²-xy-2y²)(3x+3y)
=（x²+2xy+y²)/(x²-xy-2y²)(3x+3y)
=(x+y)²/(x²+xy-2xy-2y²)3(x+y)
=(x+y)/3[x(x+y)-2y(x+y)]
=(x+y)/3(x+y)(x-2y)
=1/3(x-2y)
不知道你满意不
我写的比较详细
你看懂了之后可以简化点

收起

你是小学生吗？晕，同分就可以看出答案了，我看初中生都会！！

x²-2xy+y²-9 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 因式分解 x²-XY-2y²-X-Y x²+xy-2y²-x+7y-6 因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急 （xy-x²）÷[（x²-2xy+y²）÷xy]*[(x-y)÷x²] x²-4y² x+2y---------- ÷ --------分数线x²+2xy+y² x²+xyx²-4y² x+2y----------÷--------分数线x²+2xy+y² x²+xy(x+2y)(x-2y)x(x+y)=----------------(x+y)(x+y)(x+2y)(x-y)x=------(x+y)这样对了吗? x²-y²+6x+9分之x²+y²-9-2xy 因式分解 x²-2xy+y²-z² x/y=2,求x²-3xy+y²/2x²-3xy+5y² 已知x/y=3,求x²+2xy-3y²/x²-2xy+y² x/y=2,求分式x²-xy+3y²/x²+xy+6y² 已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值 (x+2y)²-x²-2xy