2x^2+9xy-5y^2=0,则y/x=?
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2x^2+9xy-5y^2=0,则y/x=?
2x^2+9xy-5y^2=0,则y/x=?
2x^2+9xy-5y^2=0,则y/x=?
2x^2+9xy-5y^2=0
2+9y/x-5(y/x)^2=0
(2-y/x)(1+5y/x)=0
y/x=2
或:y/x=-1/5
2x^2+9xy-5y^2=0
(2x-y)(x+5y)=0
2x=y或x=-5y
y/x=2或y/x=-1/5
2x^2+9xy-5y^2=(2x-y)(x+5y)=0
2x=y
x=-5y
y/x=2,-1/5
原式等号两边同除以y²,得:2(x/y)²+9x/y-5=0
解得:x/y=-1/2或5
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