若x^2+2x+1+y^2-8x+16=0,求x分之y的值
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若x^2+2x+1+y^2-8x+16=0,求x分之y的值
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
x^2+2x+1+y^2-8x+16=0
(x+1)²+(y-4)²=0
﹛x+1=0
y-4=0
∴x=-1,y=4
x分之y=-4
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