函数y=sin(2x+π/6)-cos(2x+π/3)的单调增区间为
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函数y=sin(2x+π/6)-cos(2x+π/3)的单调增区间为
函数y=sin(2x+π/6)-cos(2x+π/3)的单调增区间为
函数y=sin(2x+π/6)-cos(2x+π/3)的单调增区间为
y=sin(2x+π/6)-cos(2x+π/3)
=sin2x*(√3/2)+cos2x*(1/2)-cos2x*(1/2)+sin2x*(√3/2)
=√3sin2x
则单调增区间为
-π+2kπ≤2x≤2kπ
-π/2+kπ≤x≤kπ,
即为[-π/2+kπ,kπ]
把上式展开,可得根号3乘以sin2x
所以单调区间为:[-π/4,π/4]为增区间,[π/4.3π/4]为减区间
经过化简可以的y=跟号3sin2x,由图可知单调增区间-派/4+k派到派/4+k派,取闭区间
y=sin(2x+π/6)-cos(2x+π/3)
=sin(2x+π/6)+sin(2x-π/6)
=2sin2xcosπ/6
=√3sin2x,
则单调增区间为
-π/2+2kπ≤2x≤π/2+2kπ
-π/4+kπ≤x≤π/4+kπ,
即为[-π/4+kπ,π/4+kπ]。
O(∩_∩)O~
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