法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
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法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
法国风格的发给
①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O
图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3
②BO是∠ABC与∠ACB的外角的平分线,设∠A=x°,求∠O
图————http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=3b9792c4b90e49ebd10060a2
法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
∠O=1/2∠A=1/2X
∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+∠ACB+∠BCO+∠OCF=360°*2=720°
∴∠CBO+∠OBE+∠BCO+∠OCF=
360°-(180°-X)=180°+x
∵OB,OC分别平分∠CBE和∠BCF
∴∠CBO+∠BCO=1/2(180°+x)=90°+1/2X
∠O=180°-(900°+1/2X)=90°+1/2X
不懂可以再问哦
什么题目啊 ?
发给我 就Ok的啦
1, ∠ABE=∠A+∠ACB
∠OBC=∠O+∠OCB
∠ABE=2∠OBE ∠ACB=2∠OCB
故:∠O=1/2∠A
∠O=1/2X
∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+...
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∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+∠ACB+∠BCO+∠OCF=360°*2=720°
∴∠CBO+∠OBE+∠BCO+∠OCF=
360°-(180°-X)=180°+x
∵OB,OC分别平分∠CBE和∠BCF
∴∠CBO+∠BCO=1/2(180°+x)=90°+1/2X
∠O=180°-(900°+1/2X)=90°+1/2X
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