sin(2a-b)-2cos(a+b)sina/sinb
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sin(2a-b)-2cos(a+b)sina/sinb
sin(2a-b)-2cos(a+b)sina/sinb
sin(2a-b)-2cos(a+b)sina/sinb
sin(2a-b)-2cos(a+b)sina/sinb
=sin(2a-b)-2[sinacosacosb-sinasinasinb]/sinb
=sin(2a-b)-sin2acotb+2sin^2(a)
=sin(2a-b)-sin2acotb+1-cos2a
=sin2acosb-cos2asinb-sin2acotb+1-cos2a
=sin2acosb-sin2acotb-cos2asinb-cos2a+1
=sin2a(cosb-cotb)-cos2a(sinb+1)+1
化简cos(a+b)cos(a-b)+sin^2b
cos^2a-cos^2b=m,那么sin(a+b)sin(a-b)=?
证明sin(A+B)sin(A-B)=cos^2B-cos^2A
求证cos(a+b)cos(a-b)=cos^2b-sin^2a
求证cos(a+b)cos(a-b)=cos^2a-sin^2b
化简sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b
sin^2a+sin^2b-sin^2a * sin^2b+cos^2a * cos^2b 化简
sin^2 (A)+sin^2(B)-sin^2(A)sin^2(B)+cos^2(A)cos^2(B)
证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1
sin(a-b)*cos a-cos(a-b)*sin a=1/5,则cos 2b的值是
化简(sin(a-b)-2sin a cos b)/2sin a sin b +coa(a+b)
化简[sin(2A+B)]/sinA-2cos(A+B)
sin(2a-b)-2cos(a+b)sina/sinb
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
化简sin^2acos^b-cos^2asin^2b+cos^a-cos^2b
Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2
【(sin a+cos a)/(sin a-cos a) 】=3,tan (a-b)=2,tan (b-2a)=?
cos(A+B)cos(A-B)化简的结果是( )A.cos^2A-sin^2BB.sin^2A-sin^2BC.cos^2A-cos^2BD.sin^2A-COS^2B怎么作的?