求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 20:39:41
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值
求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
原式=sin(-1200+360*4)*cos(1230-360*3)+cos(-1020+3*360)*-sin(
-1050+360*3)
=sin(240)*cos(150)+cos(60)*sin(30)
=[-sin(60)]*[-cos(30)]+cos(60)*sin(30)
=-(√3)/2*-(√3)/2+1/2*1/2
=1
求sin(-1200°)×cos1290°+cos9-1020°)×sin(-1500°)+tan945°
求sin(-1200°)×cos1290°+cos9-1020°)×sin(-1500°)+tan95°
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855°
sin(-1200°)cos1290°+cos(-1020°)sin(-1050°)+tan855求值..
求音乐:sin( 1200度)cos1290度 cos( 1020度)in( 1050度)+tan495度
求sin(―1200°)·cos1290°+cos(―1020°)·sin(―1050°)+tan945°的值.
求sin﹙-1200°﹚·cos1290+cos﹙-1020°﹚·sin﹙-1050°﹚+tan945°的值
sin(-330°)怎么求?
求sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80°
求sin平方10°+sin平方20°+.+sin平方80°的值
求sin²1°+sin²2°+sin²3°……sin²89°=?
求sin(-1050°)三角函数值
sin(-390°)求三角函数值
求值:sin(-1920°)=求过程
sin(-210°)求详细步骤
求大神求sin
Sin(15°+x)-sin(15°-x) 求大神!Sin(15°+x)-sin(15°-x)求大神!