⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
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⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
1)=(2a+b)/[(2a+b)(2a-b)]-(2a-b)/[(2a+b)(2a-b)]
=[(2a+b)-(2a-b)]/[(2a+b)(2a-b)]
=2b/[(2a+b)(2a-b)]
=2b/(4a²-b²)
2)=x=2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)/(x-1)-(x-1)
=x²/(x-1)-(x-1)²/(x-1)
=[x²-(x-1)²]/(x-1)
=(2x-1)/(x-1)
3)=1/(x-3﹚-6/(x+3)(x-3)-﹙x-1)/2(x+3)
=2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)
=[2(x+3)-12-﹙x-1)(x-3)]/2(x+3)(x-3)
=(-x²+6x-9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=-(x-3)/2(x+3)
=(3-x)/(2x+6)
(1)原式=1/2a-b-1/2a-1/2b
=-3/2b
(2)这个式子我怕看错,不回答算了
望楼主采纳啊
5a-(-2a+3-b)+2b-1 化简:7-[5-﹙3a-2b﹚+a]+a
已知|2a-b+1|+(3a+3/2b²=0,求b²/(a+b)÷[﹙a/(a-b)-1﹚﹙a-a²/(a+b)]的值
﹙a-2b+1﹚²
(a+b)×(a+b)=a×(a+b)+b×(a+b)=(a²+ab)+(ab+b²)=a²+2ab+b².那么﹙a+b﹚﹚×﹙a-b﹚=多少
设a,b∈R,集合﹛1,a+b,a﹜=﹛0,b/a,b﹜,则b-a=﹙﹚ A,1 B,-1 C,2 D,-2
⑴当a=1/2,b=1/3时,求式子①a²-2ab+b²;②﹙a-b﹚²的值⑵当a=5,b=3时,分别求式子①a²-2ab+b²;②﹙a-b﹚²的值⑶观察⑴⑵中的结果,你能说出a²-2ab+b²与﹙a-b﹚²有何关系吗?
(a-1/2)[(a+1/2b)²-(a-1/2b)²]﹙a²+1/2ab+b²﹚-2b﹙a⁴-1﹚化简,a=2,b=-1
己知a/b=2/3,求a+b/b的值﹙a+b﹚/b
计算:﹙2a-b/a+b-b/a-b﹚÷a-2b/a-b.最好有计算过程.
(a+2b)(a-2b)﹙a²-4b²﹚.
分式的加减计算﹙1﹚a²/a-b-b²/a-b
分式的加减计算﹙1﹚a²/a-b-b²/a-b快
先化简,再求值.﹙2a-3b﹚²-﹙2a+3b﹚﹙2a-3b﹚+﹙2a+3b﹚其中a=-2,b=3分之1
a+b a-b----- -- ------a-b a+b -------------------------1------a^2 -b^2
(a-b+ab-a^2/a+b)乘以[a+1/a-b乘以(1+a/b)]
化简2a-3b-[3a-﹙2b-a﹚]-2a
分解因式⑴x³y-4x=⑵a³+2a²+a=⑶﹙-a²b﹚²•a=⑷2a^3b^4﹢12a³b²=⑸(a-1)(a+2﹚=⑹(½a-2)²=
2a^2-(b-a)a-b(b-1)