⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 23:34:45

⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚

⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-1/6+2x﹚
1)=(2a+b)/[(2a+b)(2a-b)]-(2a-b)/[(2a+b)(2a-b)]
=[(2a+b)-(2a-b)]/[(2a+b)(2a-b)]
=2b/[(2a+b)(2a-b)]
=2b/(4a²-b²)
2)=x=2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)/(x-1)-(x-1)
=x²/(x-1)-(x-1)²/(x-1)
=[x²-(x-1)²]/(x-1)
=(2x-1)/(x-1)
3)=1/(x-3﹚-6/(x+3)(x-3)-﹙x-1)/2(x+3)
=2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)
=[2(x+3)-12-﹙x-1)(x-3)]/2(x+3)(x-3)
=(-x²+6x-9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=-(x-3)/2(x+3)
=(3-x)/(2x+6)

(1)原式=1/2a-b-1/2a-1/2b
=-3/2b
(2)这个式子我怕看错,不回答算了
望楼主采纳啊