log2(3)-log4(6)怎么算
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log2(3)-log4(6)怎么算
log2(3)-log4(6)怎么算
log2(3)-log4(6)怎么算
log2(3)-log4(6)
= log2(3)-log2^2((√6)^2)
= log2(3)-log2(√6)
= log2(3/√6)
= log2(√3/√2)
= log2(√3)-log2(√2)
= 1/2log2(3) - 1/2
如果题目是【log2(3)-log4(36)】
log2(3)-log4(36)
= log2(3)-log2^2((6)^2)
= log2(3)-log2(6)
= log2(3/6)
= log2(1/2)
= -1
log4(6)=log2(6)/log2(4)=[log2(2)+log2(3)]/log2(4)=[1+log2(3)]/2=1/2+log2(3)
log2(3)-log4(6)=log2(3)/2-1/2
log4(3) log8(3) =log2(3)/log2(4) log2(3)/log2(8)
=0.5log2(3) 1/3*log2(3)
=5/6*log2(3)
在高中阶段运算到这一步化为单个对数就可以了,主要运用的是换底公式。
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