计算:x/3+[1-1/2(4x-1)]=1
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 19:47:18
计算:x/3+[1-1/2(4x-1)]=1
计算:x/3+[1-1/2(4x-1)]=1
计算:x/3+[1-1/2(4x-1)]=1
x=3/10 好久没动过脑子了 ,不晓得是对不.下面的不对把
x/3+1-1/2(4x-1)=1
x/3-1/2(4x-1)=0
2x(4x-1)-3=0
8x^2-2x-3=0
(2x+1)(4x-3)=0
由此可得x=-1/2或者x=3/4
计算(x+1)(x+2)(x+3)(x+4)
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算:(2x+3)(3x-4)>(x+1)(x-1)+5x(x+3)+7
计算:(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程
计算-4x(3x²-2x-1)
计算-4x(3x²-2x-1)
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
计算(x+2)/(x+1) - (x+3)/(x+2) + (x+4)/(x+3) - (x+5)/(x+4)
如何计算(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
计算:(3/x)+(x/x²-1)-(4/1-x)
计算:(x+1)(x-2)(x-3)(x-6)
计算 x(x+3)-(x-1)(x-2)
计算:x/(x-1)-(x+3)/(x^-1)*(x^2+2x+1)/(x+3)
计算:1-2x+x^2/x-x^3*xy+x^2y/x-x^2