已知x+y=7,xy=10,求3x²+3y².
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已知x+y=7,xy=10,求3x²+3y².
已知x+y=7,xy=10,求3x²+3y².
已知x+y=7,xy=10,求3x²+3y².
3x²+3y²
=3(x²+y²)
=3(x+y)²-6xy
=3×7²-6×10
=147-60
=87
x+y=7,xy=10
解得 x=2,y=5
代入可得 3x²+3y²=87
3x²+3y²
=3(x²+y²)
=3(x+y)²-6xy
=3*49-6*10
=87
(x+y)²-2xy=x²+y²
x²+y²=29
3x²+3y²=87
3x²+3y²=3(x²+y²)=3【(x+y)²-2xy】=3(49-20)=87
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