(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/03 02:24:02

(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)

(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
=x(x+3)(x-2)(x-1)/x(1-x)(x+3)(x-2)
=-1

[ (x-x²)(x²+x-6)]分之[(x²+3x)(x²-3x+2)]?
=[(x²+3x)(x²-3x+2)]/[ (x-x²)(x²+x-6)]
=[x(x+3)(x-1)(x-2)]/[ x(1-x)(x-2)(x+3)]
=-1