(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
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(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
=x(x+3)(x-2)(x-1)/x(1-x)(x+3)(x-2)
=-1
[ (x-x²)(x²+x-6)]分之[(x²+3x)(x²-3x+2)]?
=[(x²+3x)(x²-3x+2)]/[ (x-x²)(x²+x-6)]
=[x(x+3)(x-1)(x-2)]/[ x(1-x)(x-2)(x+3)]
=-1
(x-x2)(x2+x-6)分之(x2+3x)(x2-3x+2)
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