是希望杯的23.As in right figure,in a quadrilateral ABCD,we have its diagonal AC bisects DAB,and AB=21,AD=9,BC=DC=10,then the distancefrom point C to line AB is ,and the length of AC is .(英汉词典:quadrilateral 四边形;bisect
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是希望杯的23.As in right figure,in a quadrilateral ABCD,we have its diagonal AC bisects DAB,and AB=21,AD=9,BC=DC=10,then the distancefrom point C to line AB is ,and the length of AC is .(英汉词典:quadrilateral 四边形;bisect
是希望杯的
23.As in right figure,in a quadrilateral ABCD,we have its diagonal AC
bisects DAB,and AB=21,AD=9,BC=DC=10,then the distance
from point C to line AB is ,and the length of AC is .
(英汉词典:quadrilateral 四边形;bisect 平分)
是希望杯的23.As in right figure,in a quadrilateral ABCD,we have its diagonal AC bisects DAB,and AB=21,AD=9,BC=DC=10,then the distancefrom point C to line AB is ,and the length of AC is .(英汉词典:quadrilateral 四边形;bisect
过C作CE垂直于AD延长线,CF垂直于AB,易证三角形CED全等于三角形CFB,三角形CAD全等于三角形CAF,设BF=X,则DE=X,所以可得方程21-X=9+X,解得X=6.由勾股定理可求,CE=CF=8,AC=17,即from point C to line AB is 8,and the length of AC is 17
过C作CE垂直于AD延长线,CF垂直于AB
由AC平分角DAB,易证三角形CEA全等于三角形CDB,得CF=CE
进而的三角形CED全等于三角形CFB,设BF=X,则DE=X,所以可得方程21-X=9+X,解得X=6。由勾股定理可求,CE=CF=8,AC=17,即from point C to line AB is 8,and the length of AC is 17 <...
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过C作CE垂直于AD延长线,CF垂直于AB
由AC平分角DAB,易证三角形CEA全等于三角形CDB,得CF=CE
进而的三角形CED全等于三角形CFB,设BF=X,则DE=X,所以可得方程21-X=9+X,解得X=6。由勾股定理可求,CE=CF=8,AC=17,即from point C to line AB is 8,and the length of AC is 17
一楼有几处三角形三个点写错了!!很明显"三角形CAD全等于三角形CAF"是错的
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