若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
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若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
若X^2+y^2+2x-6y+10=0,求y^2x-x^2011的值
x^2+y^2+2x-6y+10=x^2+2x+1+y^2-6y+9=(x+1)^2+(y-3)^2=0;
由于(x+1)^2和(y-3)^2都是≥0的,所以只能他们分别等于0才可能和为0.
那么x=-1,y=3.
求得:y^2x-x^2011=-8 【如果是(y^2)·x的话..如果是y^(2x)那么应该等于10/9】
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