x+3y-2=0,则3^x+27^y+3的最小值是多少
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x+3y-2=0,则3^x+27^y+3的最小值是多少
x+3y-2=0,则3^x+27^y+3的最小值是多少
x+3y-2=0,则3^x+27^y+3的最小值是多少
3^x+27^y+3=3^x+3^(3y)+3=3^x+3^(2-x)+3
设3^x=t t>0
3^x+27^y+3=3^x+3^(3y)+3=3^x+3^(2-x)+3=t+9/t+3
最小值当且仅当t=9/t,即t=3时候取得,为 9
3^x+27^y+3=3^(X+3Y)+3
x+3y-2=0
x+3y=2
所以3^x+27^y+3=12
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