求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
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求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
sin(x+y)/sin(x-y)
=(sinxcosy+cosxsiny)/(sinxcosy-cosxsiny) 上下都除以cosxcosy
=(tanx+tany)/(tanx-tany)
求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(si求证.(tanx+tany)/(tanx-tany)=(sinx+siny)/(sinx-siny)
tan(x+y)=tanx+tany吗
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)
化简tan(x+y)—tanx—tany / tan(x+y)tanx
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)(详细步骤)
高手进tanx+tany/tanx-tany=3/2 求tanx/tany?
若tanx=2,tany=3,求tan(x-y)
tanx=2,tan(x-y)=-3/5,则tany=?
已知tanx=1/4,tany=-3,求tan(x+y)的值
已知:tanx=1/3,tany=-2.求tan(x+y)若0度
tan(x+y)=7,tanx*tany=2/3,则cos(x-y)=?
tanX=2分之1,tan(x+y)=5分之2,那么tanY=?
tanx+tany=25,cotx+coty=30.tan(x+y)=?RT
tanx+tany=25 cotx+coty=30,那么tan(x+y)=?
已知tanx=-3/4,且tan(x+y)=1,求tany的值
tan(x+y)=0是tanx+tany=0成立的什么条件
若0≤x-y<π/2,且tanx=3tany,则x-y的最大值为?tan(x-y)=(tanx-tany)/(1+tanxtany)=2tany/(1+3tan^2y)=2/(1/tany+3tany)为什么是小于等于这个呢?不懂 ≤2/2√(1/tany*3tany)
如果实数x,y满足|tanx|+|tany|>|tanx+tany|,且y∈(π,3π/2),则|tanx-tany|等于