关于初二异分母的分式加减法的计算题1、(X²/X-1)-x+12、(a²+b²/a²-b²)-(a-b/2a+2b)3、(3x-1/x+2)-(2x+1/3-x)4、(x+1/x-2)-(2x+1/x-1)
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关于初二异分母的分式加减法的计算题1、(X²/X-1)-x+12、(a²+b²/a²-b²)-(a-b/2a+2b)3、(3x-1/x+2)-(2x+1/3-x)4、(x+1/x-2)-(2x+1/x-1)
关于初二异分母的分式加减法的计算题
1、(X²/X-1)-x+1
2、(a²+b²/a²-b²)-(a-b/2a+2b)
3、(3x-1/x+2)-(2x+1/3-x)
4、(x+1/x-2)-(2x+1/x-1)
关于初二异分母的分式加减法的计算题1、(X²/X-1)-x+12、(a²+b²/a²-b²)-(a-b/2a+2b)3、(3x-1/x+2)-(2x+1/3-x)4、(x+1/x-2)-(2x+1/x-1)
1、=X2/(x-1)-(x-1)(x-1)/(x-1)=X2/(x-1)-(X2-2x+1)/(x-1)=(2x-1)/(x-1)
1、可转化为:(X²/X-1)-(x-1)(x-1)/(x-1)
=[X²-(x-1)(x-1)]/(x-1)
=[X²-(X²-2x-1)]/(x-1)
=(2x+1)/(x-1)
2、可转化为...
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1、可转化为:(X²/X-1)-(x-1)(x-1)/(x-1)
=[X²-(x-1)(x-1)]/(x-1)
=[X²-(X²-2x-1)]/(x-1)
=(2x+1)/(x-1)
2、可转化为:[a²+b²/(a+b)(a-b)]-[(a-b)/2(a+b)]
=[2(a²+b²)-(a-b) (a-b) ] /2(a+b)(a-b)
=(a+b)/2(a-b)
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2、=2a²+2b²/2(a+b)(a-b)-(a-b)²/2(a+b)(a-b)
=2a²+2b²-(a-b)²/2(a+b)(a-b)
=a²+b²+2ab/2(a+b)(a-b)
=(a+b)²/2(a+b)(a-b)
=a+b/2(a-b)