Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
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Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
Lingo 出错
model:
max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5
X2+X3+x4>=400
0.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
model:
max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5;
X2+X3+x4>=400;
0.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
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LINGO求改错目标函数:S= 约束条件:1、xi为5的倍数2、x120,h1133、xi>x(i+1)4、xi+4*hi=dLINGO程序:model:Title 1;sets:jishu/1..14/:x,h;endsets[OBJ] max=((@sum(jishu(i)|i#GT#1:(x(i)*(h(i)-h(i-1)))))+x(1)*h(1))*2;@for(jishu(i):x(i)^
lingo问题,对专业的人来说很简单的.MODEL :SETS:集合段XYI/ @FIL E(′data1txt′) / :x ,y ,r ; 定义变量ENDSETSMIN = R1 - R2 ; 目标函数;下面是约束;R1 = @MAX(XYI(J ) :r (J ) ) ; 找出半径的最大值;R2 = @MIN(XYI(J ) :r (J
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