[12(x+y)的立方+3(x+y)(x-y)的平方]÷6(x+y)=

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[12(x+y)的立方+3(x+y)(x-y)的平方]÷6(x+y)=
[12(x+y)的立方+3(x+y)(x-y)的平方]÷6(x+y)=

[12(x+y)的立方+3(x+y)(x-y)的平方]÷6(x+y)=
[12(x+y)的立方+3(x+y)(x-y)的平方]÷6(x+y)
=2(x+y)²+1/2(x-y)²
=2x²+4xy+y²+0.5x²-xy+0.5y²
=2.5x²+3xy+2.5y²
如果本题有什么不明白可以追问,

原式=3(x+y)[4(x+y)²+(x-y)²]÷6(x+y)
=(4x²+8xy+4y²+x²-2xy+y²)/2
=(5x²+6xy+5y²)/2

=2(x+y)²+(x-y)²/2
=(4x²+8xy+4y²+x²-2xy+y²)/2
=(5x²+6x6+5y²)/2