1/6x-4y + 1/6x+4y - 3x/9x^2-4y^2=过程=?
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1/6x-4y + 1/6x+4y - 3x/9x^2-4y^2=过程=?
1/6x-4y + 1/6x+4y - 3x/9x^2-4y^2=过程=?
1/6x-4y + 1/6x+4y - 3x/9x^2-4y^2=过程=?
1/(6x-4y)+(1/6x+4y)-3x/(9x^2-4y^2)
=[(6x+4y)+(6x-4y)]/[(6x+4y)(6x-4y)]-3x/(9x^2-4y^2)
=12x/(9x^2-4y^2)-3x/(9x^2-4y^2)
=9x/(9x^2-4y^2)
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
(x+y)(x-y)+4(y-1)
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
(-x+6):(x-y);(4x+y)=3;14:1,求x+y的值.
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
1.(x-2y)(x+2y)-(x平方+y)(x平方-y) 2.(2x-y)(y+2x)-(2y+x)(2y-x)3.已知:x+y=6,x平方-y平方=48,求x,y的值4.x平方-2x分之x+2 -- x平方-4x+4分之x-1
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
把(x-y)看作一个整体,化简:(1)5(x-y)+2(x-y)-4(x-y);(2)3(x-y²-4(x-y)+7(x-y)-6(x-y)
要求 解方程组:{(X-1)(Y+1)=(X+1)(Y+1){X(2+Y)-6=Y(X-4)
2(x-y)/3-(x+y)/4=-1 (1) 6(x+y)-4(2x-y)=16 (2)
2/x-y + 6/x+y = 11/10 分式方程组 4/x-y - 6/x+y =1/10
解二元一次方程组3(x+y)-4(x-y)=4 x+y/2+x-y/6=1
解方程组2(x-y)/3-x+y/4=-1 6(x-y)-4(2x-y)=16
解方程组3(x+y)-4(x-y)=4和(x+y)/2+(x-y)/6=1kkkkkkkk
解方程组3(x+y)-4(x-y)=4,x+y除以2+x-y除以6=1
[(3x+4y)]^2-3x(3x+4y)]/(--6y),其中x=1,y=3
解方程组:2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16