1/(1*4) + 1/(4*7) +1/(7*10)+1/(10*13) …… 1/(298*301)=
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1/(1*4) + 1/(4*7) +1/(7*10)+1/(10*13) …… 1/(298*301)=
1/(1*4) + 1/(4*7) +1/(7*10)+1/(10*13) …… 1/(298*301)=
1/(1*4) + 1/(4*7) +1/(7*10)+1/(10*13) …… 1/(298*301)=
=1/3*(1-1/4)+1/3*(1/4-1/7)+……+1/3*(1/298-1/301)
=1/3*(1-1/4+1/4-1/7+……+1/298-1/301)
=1/3*(1-1/301)
=100/301
1,4,7,(),16 1,4,7,(),20 1,4,7,(),24
1,2,4,7,(),(),().
计算,1/(1*4)+1/(4*7)+1/(7*10)+1/(10*13).1/(97*100)
(7/20-5/36)*4-4/9 【1-(1/4+3/8)】/1/4
初一简便运算6(7+1)(7^2+1)(7^4+1)(7^8+1)+16*(7+1)*(7^2+1)*(7^4+1)*(7^8+1)+1
4分之3-(7分之1-4分之1)
先化简,再求值:6(7+1)(7²+1)([7^4]1)([7^8]+1)+1
(1)1+1/2+1/3+1/4+1/5+1/6+1/7+1/14+1/28
1*4/3+4*7/3+7*10/3+.2008*2011/3 简便算法(50/1-1)(49/1-1)(48/1-1)......(4/1-1)(3/1-1)(2/1-1)
(7-1):(4-1)=(11-1):(x-1)怎么解
7X(7X+1)+4分1 二次方程
1、1、2、4、7、11、()、()
1*4/1+4*7/1+7*10/1+……+2008*2011/1的值 前提是根据 1*4/1=3/1*(1-4/1)*等于乘 1*4/1就是1×4分之1
计算:1/(1x4)+1/(4x7)+1/(7x10)…+1/(298x301)
(1+1/2)*(1+1/4)*(1+1/6)*...*(1+1/2008)*(1-1/3)*(1-1/5)*(1-1/7)*...*(1-1/2007)
请详细说明简算方法,(4又1/19-1/17)*(1/7+1/8+1/9)-4*(1/7-1/8+1/9)+(1/7+1/8+1/9)*(1/17-1/19)
(1/2-1/3)+(1/4-1/5)+(1/7-1/10)+(1/14-1/15)+(1/28-1/30)要求简便运算.
简便计算:1、1/3+1/6+1/10+1/15+1/21+1/28+.+1/1202、1/4+1/12+1/24+1/40+.+1/198003、1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+.+1/(1+2+3+4+.+50)4、(3*3-1)/(3*3+1)+(5*5-1)/(5*5+1)+(7*7-1)/(7*7+1)+.+(1995*1995-1