1.y=sin(1/2x+π/6),x属于[0,π/3] 2.y=-cos(3x-π/3),x属于[-π/3,π/3]

判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少, y=sin(x-π/6) 和 y=1/2sin(π/3-2x) 的单增区间, 1.y=sin(-X+π/6)2.y=cos(-2X+π/3) 1.y=sin(1/2x+π/6),x属于[0,π/3] 2.y=-cos(3x-π/3),x属于[-π/3,π/3] y=12sin(2x+π/6)+5sin(π/3-2x)最大值 y=12sin(2x+π/6)+5sin(π/3-2x)的最大值 函数y=2sin(π/3-X)+sin(π/6+X)的最大值 1.y=x*e^(2x) 2.y=(sin(2x))/x 3.y=sin(3x+(π/3))怎么求导数! y =sin(2x-1)求导! 解微分方程：x(y´+1)+sin(x+y)=0, y(π/2)=0 y=1-x^2 x>=0 ,y=sin|x|/x x y=(sin x + COS x)^2 函数y=2sin(2x+π/6) ( -π y=sinx的图像经过怎样的变换就能得到下列函数的图像?1.y=sin(x+π/4）2.sin(2x-π/3)3.y=5sin(3x-π/4)4.y=1/2sin(1/3x+π/6) 函数y=2sin(2x-π/6)(0 已知y=sin(2x+π/6) 求值域 y=sin(π/6-2x)的周期是多少?