作业帮我想知道这题数学题的答案和做法...不过题目是英文的Two circles each have radius 10cm.They overlap so that each contain exacty 25% lthe other's circumference.The area of the shaded region is of closest to...A)57.08cm² B)55.24
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我想知道这题数学题的答案和做法...不过题目是英文的Two circles each have radius 10cm.They overlap so that each contain exacty 25% lthe other's circumference.The area of the shaded region is of closest to...A)57.08cm² B)55.24
我想知道这题数学题的答案和做法...不过题目是英文的
Two circles each have radius 10cm.They overlap so that each contain exacty 25% lthe other's circumference.The area of the shaded region is of closest to...
A)57.08cm² B)55.24cm² C)51.83cm² D)54.17cm² E) 53.21cm²
我想知道答案 和 ....
我可能没有说清楚...我想要的答案是两个圆重叠的部分
我想知道这题数学题的答案和做法...不过题目是英文的Two circles each have radius 10cm.They overlap so that each contain exacty 25% lthe other's circumference.The area of the shaded region is of closest to...A)57.08cm² B)55.24
两个圆,每个圆半径都为10cm.两个圆互相重叠以至于每个圆都包含另外圆的25%圆周长.重叠区域的面积最接近于.
25%的圆周长 连接两交点到圆心,则两直线的夹角为90度
则重叠区域的面积为 两个半径为10cm角度为90度的扇形面积减去两个等边直角形的面积,直角边边长为10cm
2*(3.1416*10*10/4)-2(10*10/2)=(3.1416/2-1)*100=57.08
不就是求两个90度弓形的面积和嘛。一个圆面积314平方cm,内接正方形14.14*14.14.两者相减除以二就好了。
A
就是用两个90度扇形的面积和减去一个正方形的面积