1/8+1/24+1/48+1/80……+1/2400=?
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1/8+1/24+1/48+1/80……+1/2400=?
1/8+1/24+1/48+1/80……+1/2400=?
1/8+1/24+1/48+1/80……+1/2400=?
1/8+1/24+1/48+1/80……+1/2400
=(1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10+……+1/48-1/50)÷2
=(1/2-1/50)÷2
=6/25
1/8+1/24+1/48+1/80……+1/2400=?
1/8+1/24+1/48+1/80
1/8+1/24+1/48+1/80简便计算
1-2/3-1/6-1/12-1/24-1/48-……1/768
1 3 8 15 24 ☆ 48 63……☆是多少?
(1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64=
(1/8+1/24+1/48+1/80+1/120+1/168+1/224)乘64
3/8÷[(1/5+1/4)×3/8] 2/2×4+2/24+2/48……+2/9800
若一组按规律排成的数为:3,8,-15,24,35,-48,63,80,-99……,则这组数的第3n+1项是
3^2-1=8*1 5^2-1=24=8*3 7^2-1=48=8*6……3^2-1=8*1,5^2-1=24=8*3,7^2-1=48=8*6,9^2-1=80=8*10……问:根据上述的式子,你发现了什么?你能用数学式子来说明你的结论是正确的吗?
1+8+16+24+…+8n
(1/8+1/24+1/48+1/80+1/120+1/168)简便计算
(1/8+1/24+1/48+1/80+1/120+1/168)乘以56
(8/1+24/1+48/1+80/1+120//1+168/1)*42
1/8+1/24+1/48+1/80+1/120+1/168
(1/8+1/24+1/48+1/80+1/120+1/168)*56
42x(8/1+24/1+48/1+80/1+120/1+168/1)=?求求
42X(1/8+1/24+1/48+1/80+1/120+1/168)求解