解一2元1次方程;72%χ+58%y=62%﹙x+y﹚;72%﹙x+152﹚+58%﹙y+152﹚=63.25%﹙x+y+304﹚

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解一2元1次方程;72%χ+58%y=62%﹙x+y﹚;72%﹙x+152﹚+58%﹙y+152﹚=63.25%﹙x+y+304﹚
解一2元1次方程;72%χ+58%y=62%﹙x+y﹚;72%﹙x+152﹚+58%﹙y+152﹚=63.25%﹙x+y+304﹚

解一2元1次方程;72%χ+58%y=62%﹙x+y﹚;72%﹙x+152﹚+58%﹙y+152﹚=63.25%﹙x+y+304﹚
72%χ+58%y=62%﹙x+y﹚ ①
72%﹙x+152﹚+58%﹙y+152﹚=63.25%﹙x+y+304﹚ ②
由①得10x=4y x=2y/5
由②得8.75x-5.25y=-532
将x=2y/5带入上式得
8.75×2y/5-5.25y=-532
-1.75y=-532
y=304
所以x=2y/5=2×304/5=121.6

X=121.6 Y=304

有1方程得x=0.4y代入2方程得y=304,即的x=121.6

x=121.6
y=304