(x2+y2)(x2-xy+y2)-2x2y2因式分解
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(x2+y2)(x2-xy+y2)-2x2y2因式分解
(x2+y2)(x2-xy+y2)-2x2y2因式分解
(x2+y2)(x2-xy+y2)-2x2y2因式分解
打开,然后再整理,就可以了~
(x2+y2)(x2-xy+y2)-2x2y2
= x4 -x3y +2x2y2 -xy3 + y4 - 2x2y2
= x4 + y4 - x3y - xy3
= (x-y)(x3-y3)
= (x-y)(x-y)(x2+xy+y2)
= (x-y)^2 * (x^2 +xy +y^2) (^表示平方)
(x-y)(x2+xy+y2)
(x+y)(x2-xy+y2)
4x2-y2/x2-2xy+y2 +(2x-y)/2x2-2xy
计算(x+y/x-y + 4xy/y2-x2)(x2-9y2)/(x2+2xy-3y2)
(x2+2xy+y2)( x2-xy+y2)2 化简
(x2-2xy+y2)-(x2+2xy+y2)=什么
( x2+xy+y2) ( x2+xy+2y2)-12y4
(x2+xy+y2)-4xy(x2+y2)
x2-2xy+y2-9
x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式
2(x-xy)-3(2x2-3xy)2[x2(2x2-xy+y2)]
已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=
(x2+y2)(x2-xy+y2)-2x2y2因式分解
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