sin(360--x)cos(180+x)cos(90+x)
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sin(360--x)cos(180+x)cos(90+x)
sin(360--x)cos(180+x)cos(90+x)
sin(360--x)cos(180+x)cos(90+x)
sin(360--x)cos(180+x)cos(90+x)
=(-sinx)(-cosx)(-sinx)
=-sin^2xcosx
答:
sin(360°-x)cos(180°+x)cos(90°+x)
=sin(-x)cos(180°-x)[-cos(90°-x)]
=(-sinx)(-cosx)(-sinx)
=-sin²xcosx
sin(360--x)cos(180+x)cos(90+x)
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