cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的?
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cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的?
cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)²
cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的?
cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的?
因为cos(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)
所以cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)²
cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的?
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