已知x^2-3x+1=0求x^4-5x^3+10x^2-11x+5

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已知x^2-3x+1=0求x^4-5x^3+10x^2-11x+5
已知x^2-3x+1=0求x^4-5x^3+10x^2-11x+5

已知x^2-3x+1=0求x^4-5x^3+10x^2-11x+5

等于十

x^4-5x^3+10x^2-11x+5
=x^2(x^2-3x+1)-2x(x^2-3x+1)+3(x^2-3x+1)-1
=-1

不落

x^4-5x^3+10x^2-11x+5
=x²(x²-3x+1)-2x³+9x²-11x+5
=-2x(x²-3x+1)+3x²-9x+5
=3(x²-3x+1)+2
=2