数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=2/5求a2010
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数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=2/5求a2010
数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=2/5求a2010
数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=2/5求a2010
利用递推式,求出前几项,看规律
a1=2/5
0
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