log2 20-log4 25
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log2 20-log4 25
log2 20-log4 25
log2 20-log4 25
原式=log2 2^2+log2 5-log2^2 5^2
=2+log2 5-log2 5(换底公式)
=2
log2 20-log4 25
log2 20-log4 25的答案是
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
log2 20---log2 5+log3 4 * log4 3 等于什么
log2(20)-log2(5)+2log3(2)×log4(3)
log的计算log2为底 20-log4为底 25
log2 20-log4 25=?我要步奏.我是个S,B要最详细的
log4(log2^x)=log2(log4^x)求log2^x
log4^25-2log4^10+log2^9×log3^根号5×log5^2
log2^x=log4^9
2log2为什么等于log4
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
log4 243 - log8 729=?log4 12 - log2 6=?
3^log9(25)+16^log4(2)-(根号7)^log7(9)+(-1)^log2(1)
求值:3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))=
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
log2(X+1)+log0.25(X-1)>log4(2X-1)的解为多少?
log4 25怎么化成log2 回答都很好,不过一楼是匿名,