y=√3sin(2x-pai/6)+2sin^2(x-pai/12)的最小正周期

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y=√3sin(2x-pai/6)+2sin^2(x-pai/12)的最小正周期
y=√3sin(2x-pai/6)+2sin^2(x-pai/12)的最小正周期

y=√3sin(2x-pai/6)+2sin^2(x-pai/12)的最小正周期
y=√3sin(2x-π/6)+2[1-cos(2x-π/6)]/2
=√3sin(2x-π/6)-cos(2x-π/6)+1
=2[√3/2*sin(2x-π/6)-1/2*cos(2x-π/6)]+1
=2[sin(2x-π/6)cosπ/6-cos(2x-π/6)sinπ/6]+1
=2sin(2x-π/6-π/6)+1
=2sin(2x-π/3)+1
所以T=2π/2=π