已知x-y=1,xy=2,求x³y-2x²y²+xy³的值

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已知x-y=1,xy=2,求x³y-2x²y²+xy³的值
已知x-y=1,xy=2,求x³y-2x²y²+xy³的值

已知x-y=1,xy=2,求x³y-2x²y²+xy³的值
原式=xy(x²-2xy+y²)
=xy(x-y)²
=2×1²
=2

x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy(x-y)²
=2×1²
=2

x3y-2x2y2+xy3
=xy(x^2-2xy+y^2)
=xy(x-y)^2
=2*1=2

给个提示(x²-2xy+y²)*xy会了吧

由x-y=1有(x-y)²=1
x³y-2x²y²+xy³=xy(x²-y²)=2×1=2