tan(kπ+α)=?cos(kπ+α)=?
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tan(kπ+α)=?cos(kπ+α)=?
tan(kπ+α)=?cos(kπ+α)=?
tan(kπ+α)=?cos(kπ+α)=?
tan(kπ+α)
=tanα
cos(kπ+α) =cosα ; if n=0,2,4,6,8...
=-cosα ; if n=1,3,5,...
tan(kπ+α)=α
cos(kπ+α)=
-α,k是奇数
α,k是偶数
tan(kπ+α)=?cos(kπ+α)=?
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