y'=-2xy;求f(x).
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y'=-2xy;求f(x).
y'=-2xy;求f(x).
y'=-2xy;求f(x).
y'= -2xy,
即dy/y =-2x*dx,
对等式两边同时积分得到,
lny= -x²+C (C为常数)
所以
y=e^(-x²+C) (C为常数)
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