1*2+2*3+3*4+……+n(n+1)=
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1*2+2*3+3*4+……+n(n+1)=
1*2+2*3+3*4+……+n(n+1)=
1*2+2*3+3*4+……+n(n+1)=
将n(n+1)拆成n^2+n,每一项相加就是
1*2+2*3+3*4+……+n(n+1)
=(1^2+2^2+.+n^2)+(1+2+3+.n)
=n(n+1)*(2n+1)/6+n*(n+1)/2,
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