∫|x-1|x^3dx=? (-1
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∫|x-1|x^3dx=? (-1 ∫|x-1|x^3dx=? (-1
∫|x-1|x^3dx=? (-1
∫|x-1|x^3dx=?(-1
∫cos((x/3)-1)dx=?
∫ e^(-3x+1)dx=
∫1/x(1+x^3)dx
∫x+1/(x-1)^3dx
求∫x/(1+x)^3 dx
∫ x/ (1+x)^3 dx
∫dx/x(x^3+1)
∫x^3/1+x^2 dx
∫(x-1)^2/x^3 dx
∫(X^3)/(1+X^2)dx
∫1/(x^3+x) dx
∫ x/(1+X^2)dx=
∫(x+1/x)^2dx=?
∫dx/x(1+x)
x-9/[(根号)x]+3 dx ∫ x+1/[(根号)x] dx ∫ [(3-x^2)]^2 dx
∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷
这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx =
计算∫3 1(x+1/x)dx=