M>N>0,M^2+N^2=4MN,求m^2-N^2 分之 mn
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M>N>0,M^2+N^2=4MN,求m^2-N^2 分之 mn
M>N>0,M^2+N^2=4MN,求m^2-N^2 分之 mn
M>N>0,M^2+N^2=4MN,求m^2-N^2 分之 mn
已经详细回答,因为m^2+n^2=4mn ==>m^2-2mn+n^2=2mn ==>(m-n)^2=2mn ==> m-n=√2mn m^2+n^2=4mn ==>m^2+2mn+n^2=6mn ==>(m+n)^2=6mn ==> m+n=√6mn 因为(m^2-n^2)/mn =(m+n)(m-n)/ mn =√2mn * √6mn /mn =2√3mn/mn =2√3
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