log2 24-1/log3 2=

log2 24-1/log3 2= 为什么log3(2)=1/log2(3). log2(3)+log3(5)+log3(2)=? (log2 6)×(log3 6)-(log2 3+log3 2)= (log2 6)×(log3 6)-(log2 3+log3 2)= log2(3)*log3(2)=? (log3^2)(log2^3)= 已知log3^(a+1)=2 ,则log2^a=? log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? 计算(log3 2)(log2 6-1) log2 1-lg3×log3 2-lg5 log2 1-lg3×log3 2-lg5 解方程：log4{2log3[1+log2(1+3log2 x)]}=1/2 计算(log3(2))*(log2(6-1))=?__________尤其是(log2(6-1))=? log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12= log2[log3[log5 125]]=?log2[log3[log5 125]]=? log2(6)*log3(6)-[log2(3)+log3(2)]的值 log2(6)*log3(6)-[log2(3)+log3(2)]的值